あ，そうか・・・．外側を隠すっつーのなら対等に混ぜればいいわけじゃん．
＃うぎゃー！！これバグじゃ・・・？標準規格的には完璧にOKなはずにゃ〜！！
＃まぢかよ・・・．これ曖昧なのかよ・・・．オーバーロードにしてくれてもいいじゃ〜ん．ぶ〜ぶ〜ぶ〜．
うむぅ〜．打つ手なし・・・．ちぇっ，つまんないの〜〜〜．
10.2 Member name lookup
2 The following steps define the result of name lookup in a class scope, C. First, every declaration for the name in the class and in each of its base class sub-objects is considered. A member name f in one subobject B hides a member name f in a sub-object A if A is a base class sub-object of B. Any declarations that are so hidden are eliminated from consideration. Each of these declarations that was introduced by a using-declaration is considered to be from each sub-object of C that is of the type containing the declaration designated by the using-declaration. If the resulting set of declarations are not all from sub-objects of the same type, or the set has a nonstatic member and includes members from distinct sub-objects, there is an ambiguity and the program is ill-formed. Otherwise that set is the result of the lookup.
struct A
{
void f(int);
};
struct B
{
void f(char);
};
struct C
: public A
, public B
{ };
C().f(0); // エラー．曖昧．（オーバーロードとして扱ってくれない）あ，ちなみに上のはusing-declaration使えばできるのは承知してます．私がやりたいのはとある理由があってusing-declarationを使わずに同じ名前を単一のクラススコープに混合したいというものです．
